[tex]Use\ a^{-n}=\dfrac{1}{a^n}\\\\\boxed{11^{-4}=\dfrac{1}{11^4}=\left(\dfrac{1}{11}\right)^4}[/tex]
really omg my answer was deleted bc i didnt show work literally helper below me just chill out
anyways your answer is [tex]\frac{1}{11^{2}}[/tex] because any number to a negative exponent is 1 over that number to the exponent, but positive this time.