calculate the percentage composition of Mg3 (Po4)2

Mg3(PO4)2 - the molar mass would be 262g/mol, which is 100%

Atomic mass of Mg is 24, since we have 3Mg we multiply by 3 and get a mass of 72

262 : 100% = 72 : x%

x = 72*100 / 262

x = 27.5%

And do that for every element — get the molar mass of P and multiply by 2, use a ratio, and get the molar mass of O and multiply by 8 and use ratios :)

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Eduard22sly Eduard22sly · Answer 2 · 2021-10-21T12:45:30+02:00

The percentage composition of

Mg₃(PO₄)₂ are:

1. Percentage composition of Mg = 27.48%

2. Percentage composition of P = 23.66%

3. Percentage composition of O = 48.86%

We'll begin by calculating the molar mass of Mg₃(PO₄)₂. This can be obtained as follow:

Molar mass of Mg₃(PO₄)₂ = (24×3) + 2[31 + (16×4)]

= 72 + 2[31 + 64]

= 72 + 2[95]

= 72 + 190

= 262 g/mol

1. Determination of the percentage composition of Mg in Mg₃(PO₄)₂

Molar mass of Mg₃(PO₄)₂ = 262 g/mol

Mass of Mg in Mg₃(PO₄)₂ = 24×3 = 72 g

Percentage composition of Mg =?

[tex]Percentage = \frac{mass of element}{mass of compound} * 100\\\\= \frac{72}{262} * 100\\\\[/tex]

Percentage composition of Mg = 27.48%

2. Determination of the percentage composition of P in Mg₃(PO₄)₂

Molar mass of Mg₃(PO₄)₂ = 262 g/mol

Mass of P in Mg₃(PO₄)₂ = 31×2 = 62 g

Percentage composition of P =?

[tex]Percentage = \frac{mass of element}{mass of compound} * 100\\\\= \frac{62}{262} * 100\\\\[/tex]

Percentage composition of P = 23.66%

3. Determination of the percentage composition of O in Mg₃(PO₄)₂

Percentage composition of Mg = 27.48%

Percentage composition of P = 23.66%

Percentage composition of O =?

Percentage composition of O = 100 – (27.48 + 23.66)

Percentage composition of O = 48.86%

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