a 0.10kg piece of copper at an initial temperature of 95C is dropped into 0.20kg of water contained in a 0.28kg aluminum calorimeter. the water and calorimeter are initially at 15C. what is the final temperature of the system when it reaches equilibrium?

Respuesta :

Use the law of conservation of energy and assuming no heat loss to the surroundings, then  

Heat given up by copper = heat absorbed by water + heat absorbed by calorimeter  

Working formula is  

Q = heat = MCp(delta T)  

where  

M = mass of the substance  

Cp = specific heat of the substance  

delta T = change in temperature  

Heat given up by copper = 0.10(387)(95 - T)  

Heat absorbed by water = 0.20(4186)(T - 15)  

Heat absorbed by calorimeter = 0.28(899)(T - 15)  \

where  

T = final temperature of the system  

Substituting appropriate values,  

0.10(387)(95 - T) = 0.20(4186)(T - 15) + 0.28(899)(T - 15)  

38.7(95 - T) = 1088.92(T - 15)  

3676.50 - 38.7T = 1088.92T - 16333.8  

1127.62T = 20010.3  

T = 17.75 C

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