Answer:
Pumping gas into take with greater rate of change.
Step-by-step explanation:
Rate of change is equal to change in number of gallons per minutes.
Here we have two case
Case 1: Filling swimming pool with 100 gallons of water in 15 minutes.
So, we find how many gallons fill in 1 minutes.
[tex]\text{Rate }=\frac{\text{Number of gallons}}{\text{Total minutes}}[/tex]
[tex]\text{Rate }=\frac{100}{15}\approx 6.67\text{ gallons/min}[/tex]
Case 2: Pumping 12 gallons of gas into tank in 3 minutes.
So, we find how many gallons fill in 1 minutes.
[tex]\text{Rate }=\frac{\text{Number of gallons}}{\text{Total minutes}}[/tex]
[tex]\text{Rate }=\frac{12}{3}\Rightarrow 4\text{ gallons/min}[/tex]
Rate of case 2 is greater than case 1.
Thus, Pumping gas into tank with greater rate of change.
