Given data:
wave length (λ) = 22 cm = 0.22 m,
speed of wave length(v) = 4 m/s ,
determine the frequency (f) = ?
We know that ,
wave length and frequency of light are closely related. The higher the frequency, shorter is the wavelength and vice-versa.
Mathematically, λ = v/f -------------------- (i)
where, λ = wave length (m)
v = speed of wave length (m/s)
f = frequency (Hz)
From the equation (i) ,
frequency (f) = v/λ
= 4 / 0.22
= 18.18 /second
frequency (f) of the wave is 18 /sec or (18 Hz)
Note: frequency is defined as "number of occurrences per unit time", measured in Hz.
Answer:
c) [tex]18s^{-1}[/tex]
Explanation:
The information we have is:
Speed: [tex]v=4m/s[/tex]
wavelength: [tex]\lambda = 22cm[/tex] we need to convert this quantity to meters:
[tex]22cm=22/100m=0.22m[/tex], so [tex]\lambda =0.22m[/tex]
------------------------------------------------
We need to find the frequency of the wave, for that we use the formula:
[tex]v=f\lambda[/tex]
where [tex]f[/tex] is the frequency.
In tha last equation we clear for [tex]f[/tex]
[tex]f=\frac{v}{\lambda }[/tex]
and we substitute the known values:
[tex]f=\frac{4m/s}{0.22m}\\ f=18.18s^{-1}[/tex]
the answer is c) [tex]18s^{-1}[/tex]
