Length of the pipe = 0.39 m
Third harmonic frequency = 1400 Hz
For the third harmonic:
Wavelength = [tex]\frac{2L}{3}[/tex]
The center of the open pipe will host a node and the nearest anti - node from the center will be at the 0.25 × wavelength
Distance from center = 0.25 × wavelength
Distance = [tex]0.25 x \frac{2L}{3}[/tex]
Plugging the value of the length of the pipe (L) = 0.39 m = 39 cm
Distance = [tex]0.25 x \frac{2 \times 39}{3}[/tex]
Distance from the center to the nearest anti - node = 6.5 cm
Hence, the nearest distance to the anti - node from the center = 6.5 cm
So, option C is correct.
