The limiting reactant when 5.6 moles of aluminium react with 6.2 moles of water is
water( H2O)
Explanation
The balanced equation is as below
2 Al +3 H2O → Al2O3 +3 H2
The mole ratio of Al :Al2O3 is 2:1 therefore the moles of Al2O3
= 5.6 x1/2 = 2.8 moles
The mole ratio of H2O: Al2O3 is 3:1 therefore the moles of Al2O3 produced
= 6.2 x1/3= 2.067 moles
since H2O yield less amount of Al2O3 , H2O is the limiting reagent.
Given:
Moles of Al = 5.6 moles
Moles of H2O = 6.2 moles
To determine:
The limiting reagent
Explanation:
The chemical reaction is-
2Al + 3H2O → Al2O3 + 3H2
- Based on stoichiometry; 2 moles of Al forms 1 mole of Al2O3
Therefore, 5.6 moles of Al would give: 5.6 Al * 1 Al2O3/2 Al = 2.8 moles Al2O3
-Similarly; 3 moles of H2O forms 1 mole of Al2O2
Therefore, 6.2 moles of H2O would give: 6.2 H2O * 1 Al2O3/3 H2O = 2.07 moles Al2O3
Ans: Since the amount (moles) of Al2O3 formed from H2O is less, water is the limiting reagent.
