if it takes 3/4 of an hour for an automated sprinkler to cover 2/7 of a lawn after an hour has passed what fraction of the lawn has been convered

Respuesta :

Answer:

[tex]\frac{8}{21}[/tex]  fraction of the lawn has been covered in 1 hour.

Step-by-step explanation:

Given the statement:  if it takes [tex]\frac{3}{4}[/tex] of an hour for an automated sprinkler to cover [tex]\frac{2}{7}[/tex] of lawn.

which implies,

[tex]\frac{3}{4}[/tex] hour cover  [tex]\frac{2}{7}[/tex] of lawn

then,

in 1 hour cover [tex]\frac{\frac{2}{7} }{\frac{3}{4}} \times 1[/tex]

[Using [tex]\frac{\frac{a}{b} }{\frac{c}{d} } =\frac{a}{b} \times \frac{d}{c}[/tex] ]

= [tex]\frac{2}{7} \times \frac{4}{3} = \frac{2 \times 4}{7 \times 3} =\frac{8}{21}[/tex]                    

therefore, after an hour has passed [tex]\frac{8}{21}[/tex] of the lawn has been covered.

Answer:  [tex]\frac{8}{21}[/tex] of lawn has been covered after an hour.

Step-by-step explanation:

Since we have given that

Time taken by Automated Sprinkler is given by

[tex]\frac{3}{4}\text{ of an hour}[/tex]

Part of lawn she covered is given by

[tex]\frac{2}{7}\text{ of a lawn}[/tex]

We will use " Unitary Method" i.e.

After 1 hour, the part of lawn is covered is given by

[tex]\frac{2}{7}\times \frac{4}{3}\\\\=\frac{8}{21}[/tex]

Hence, [tex]\frac{8}{21}[/tex] of lawn has been covered after an hour.

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