Please help!! Math!!!!

5 - 3z < -10
-5 -5 minus 5 from both sides
-3z < -15
/-3 /-3 Divide both sides by 3 and when you divide by a negative you
switch the inequality sign from < to >
z > -5
Hello!
Explanation:
First, you had to do is subtract by 5 from both sides of an equation.
[tex]5-3a-5<-10-5[/tex]
And then simplify.
[tex]10+5=15[/tex]
[tex]-3a<-15[/tex]
Next, you can also multiply by -1 from both sides of an equation. It can also used by reverse inequality.
[tex](-3a)(-1)>(-15)(-1)[/tex]
Simplify by equation.
[tex]3a>15[/tex]
Then you divide by 3 from both sides of an equation.
[tex]\frac{3a}{3}> \frac{15}{3}[/tex]
Finally, simplify or dividing into the groups.
[tex]15/3=5[/tex]
*The answer must have a positive sign*
Final answer: → [tex]\boxed{a>5}[/tex]
Hope this helps!
Thanks!
Have a great day!
-Charlie