My answer is that you can multiply many different ways to git the answers and it is really easy for you if you round your factors that you are multiply.
Answer:
a). x to the power of negative 2 multiplied by y to the power of negative 6, the whole over x to the power of 8 multiplied by y to the power of negative 8
Step-by-step explanation:
Given
x multiplied by y to the power of 3 over x to the power of negative 4 multiplied by y to the power of 4, the whole to the power of negative 2.
Solving we get,
[tex]\left (\frac{xy^{3}}{x^{-4}y^{4}}\right )^{-2}[/tex]
[tex]\left (\frac{x^{5}y^{3}}{y^{4}}\right )^{-2}[/tex]
[tex]\left (\frac{x^{5}}{y}\right )^{-2}[/tex]
[tex]\left (\frac{y}{x^{5}}\right )^{2}[/tex]
[tex]\frac{y^{2}}{x^{10}}[/tex]
Now solving option A, we get
[tex]\frac{x^{-2}y^{-6}}{x^{8}y^{-8}}[/tex]
[tex]x^{-10}y^{2}[/tex]
[tex]\frac{y^{2}}{x^{10}}[/tex]
Hence proved, both are equal.
Option A is the answer.
