Respuesta :

Essentially, we just use the pythagorean theorem to solve:

7^2 + 3^2 = c^2

49 + 9 = c^2

58 = c^2

c = sqrt 58

The answer is Option D.


pythagorean theorem

for a right triangle with legs (2 sides next to the the right angle) length a and b, and hyptonuse (longest side oposite right angle) is c

[tex]a^2+b^2=c^2[/tex]


we can see that the legs are 3cm and 7cm

so a=3 and b=7 (you can do a=7 and b=3 but it doesn't matter)

[tex]a^2+b^2=c^2[/tex]

[tex]3^2+7^2=c^2[/tex]

[tex]9+49=c^2[/tex]

[tex]58=c^2[/tex]

sqrare root both sides

[tex]\sqrt{58}=c[/tex]

[tex]c=\sqrt{58}[/tex]

answer is 4th option

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