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20-11-2018
Chemistry

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How many moles of NaCl are present in 1.63 liters of a 0.954 M solution?

Respuesta :

20-11-2018

Answer:

1.56 mol

Explanation:

c = n/V Multiply both sides by V and transpose

n = Vc

c = 0.954 mol·L⁻¹

V =1.63 L Calculate the moles

n = 0.954 × 1.63

n = 1.56 mol

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