Answer: Option b
Given a quadratic equation of the form
[tex]x^2+4x=2x-7[/tex]
Let us write this in standard form of the type
[tex]ax^2+bx+C=0\\x^2+4x-2x+7=0\\Orx^2+2x+7 =0\\[/tex]
Now this equation is in std form with a =1,b=2 and c =7
Discriminant = [tex]b^2-4ac = 2^2-4(7) = -24[/tex]
Since discriminant is negative we find that there are two distinct complex solutions for this quadratic equation.
So Option b is right.
