Given the line 5x – 2y = 10, Find the equation of a parallel line that passes through the point (2, 3). Find the x- and y-intercepts of both lines. Plot the intercepts and use them to graph both lines on the same set of axes.
1) subtract 5x from both sides 2) you will be left with 2y= -5x +10 3) then you divide 2 from the three numbers 4) you will be left with y=-5/2x +5 your slope is -5/2x and your y-intercept is 5 which means your point starts at (0,5) on the graph
