??? Simplify the equation

(4^3)^5
= 4^(3*5)
= 4^15
Its D
Please note that this is not an equation ( no = sign), Its best described as an exponential expression.
Answer:
[tex]\boxed{4^{15}}[/tex]
Step-by-step explanation:
The exponent of the term decides how much times does the base needs to multiply itself. Let (4³)⁵ be known as the base (Refer to bolded text) and (4³)⁵ be known as the exponent (Refer to bolded text).
[tex]\rightarrowtail (4^{3})^{5}[/tex]
[tex]\rightarrowtail 4^{3} \times 4^{3} \times 4^{3} \times 4^{3} \times 4^{3}[/tex]
Since the terms are being multiplied by each other, we can simply add the exponents.
[tex]\rightarrowtail (4)^{3} \times (4)^{3} \times (4)^{3} \times (4)^{3} \times (4)^{3}[/tex]
[tex]\rightarrowtail (4)^{3 + 3 + 3 + 3 + 3}[/tex]
[tex]\rightarrowtail (4)^{15}[/tex]
Thus, the simplified term is 4¹⁵.