i really hope someone can hekp me with my hw
it's linear equations...

You first should isolate the "y" in the equation.
3x - 2y = 6 Subtract 3x on both sides
3x - 3x - 2y = 6 - 3x
-2y = 6 - 3x Divide -2 on both sides to get "y" by itself
[tex]y = \frac{6-3x}{-2}[/tex]
[tex]y = -3 + \frac{3}{2} x[/tex]
This equation is:
y = mx + b
"m" being the slope, "b" being the y-intercept (when x = 0)
The y-intercept is -3 in the equation. So you can eliminate choices A and C.
You can plug in any of the numbers of x(-2 , -1 , 0, 1, 2) into this equation, to find it's y value.
You can plug in 1 for x:
y = -3 + [tex]\frac{3}{2} x[/tex]
y = -3 + [tex]\frac{3}{2} (1)[/tex]
y = -3 + [tex]\frac{3}{2}[/tex] Make the denominators the same
[tex]y = \frac{-6}{2} +\frac{3}{2} = \frac{-3}{2}[/tex]
Your answer is B