First isolate the "y" in the equation.
2y - x = -12 Add x on both sides
2y - x + x = -12 + x
2y = -12 + x Divide 2 on both sides to get "y" by itself
[tex]y = \frac{-12 +x}{2}[/tex]
[tex]y = -6 + \frac{x}{2}[/tex]
Your slope is [tex]\frac{1}{2}[/tex].
For the equation of the line to be parallel to the given equation, the slopes have to be the same. So the parallel line's slope is also [tex]\frac{1}{2}[/tex]
y = mx + b
[tex]y = \frac{1}{2}x + b[/tex]
To find "b", you plug in the point (18,2) into the equation
[tex]y = \frac{1}{2}x + b[/tex]
[tex]2 = \frac{1}{2}(18) + b[/tex]
2 = 9 + b Subtract 9 on both sides
2 - 9 = 9 - 9 + b
-7 = b
Your equation is:
[tex]y =\frac{1}{2}x - 7[/tex]
