Respuesta :
m^2 + 12m + 35
We can factor using the sum-product, when the sum of 2 numbers is 12 and the product of those 2 numbers is 35.
7+5 = 12
7 x 5 = 35
So we have the numbers 7 and 5.
m^2 + 12m + 35 = (m+7)(m+5)
Answer:
[tex](m+5)(m+7)[/tex]
Step-by-step explanation:
Factor the trinomial. The factors of [tex]m^2 + 12m + 35[/tex]
In the given trinomial , the product is 35 and sum is 12
LEts find out two factors whose product is 35 and sum is 12
7 times 5 is 35
7 plus 5 is 12
Break the middle term using factors 7 and 5
[tex]m^2 + 12m + 35[/tex]
[tex]m^2 + 7m+5m + 35[/tex]
Group first two terms and last two terms
[tex](m^2 + 7m)+(5m + 35)[/tex]
Take out GCF from each group
[tex]m(m+7)+5(m + 7)[/tex]
FActor out m+7
[tex](m+5)(m+7)[/tex]