**ANSWER ASAP WILL GIVE BRAINLIEST** **PICTURES SHOWN BELOW**
3. The blue triangle (the larger one) is a dilation image of the black triangle (the smaller one) with the center at the origin. Is the dilation an enlargement of a reduction? Find the scale factor of the dilation.

4. Find the image of the vertices for a dilation with center (0,0) and a scale factor of 3.

ANSWER ASAP WILL GIVE BRAINLIEST PICTURES SHOWN BELOW 3 The blue triangle the larger one is a dilation image of the black triangle the smaller one with the cent class=
ANSWER ASAP WILL GIVE BRAINLIEST PICTURES SHOWN BELOW 3 The blue triangle the larger one is a dilation image of the black triangle the smaller one with the cent class=

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Answer:

3.

Dilation is a transformation that produces an image that is of same shape as the original, but in a different size.

*The value of scale factor ( i.,e k) determines whether the dilation is an enlargement or a reduction.

If [tex]|k|>1[/tex], then the  dilation is an enlargement.  

If [tex]|k|<11[/tex], then the dilation is a reduction.

To find the scale factor:

In other words, a dilation is a rule that moves points in the plane a specific distance, determined by the scale factor k, from a center O.

Labelled the Blue triangle as A',B', and C'

Also, for black triangle as A, B, and C as you can see the figure  shown below in the attachment.

Scale factor is given by;

k = [tex]\frac{OA'}{OA}[/tex]  where O is the origin.

From the figure, A =(1, 2.5) and A' = (2,5)

By distance formula we can find the value of OA' and OA i.e,

[tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Then,

[tex]k = \frac{OA'}{OA} = \frac{\sqrt{2-0)^2+(5-0)^2}}{\sqrt{(1-0)^2+(2.5-0)^2}} = \frac{\sqrt{2)^2+(5)^2}}{\sqrt{(1)^2+(2.5)^2}}[/tex]

or

[tex]k = \frac{\sqrt{4+25}} {\sqrt{1+\frac{25}{4}}}= \frac{\sqrt{29}} {\sqrt{\frac{29}{4}}}[/tex]

Simplify:

k = [tex]\sqrt{4} = 2[/tex] >1

therefore, by definition of scale factor, the dilation is an enlargement.

4.

Given: the center of dilation at origin (0,0) with scale factor (c) = 3.

The vertices of ABCD are;

A = (3,0)

B = (1, -2)

C = (3 , -5) and  

D = (7 , -1)

The rule of dilation with center of dilation is given by:

[tex](x , y) \rightarrow (cx , cy)[/tex] where c is the scale factor i.e, c =3

Or  we can write it as;

[tex](x , y) \rightarrow (3x , 3y)[/tex]

The images of vertices of ABCD are;

[tex]A(3, 0) \rightarrow (3 \cdot 3 , 3\cdot 0)[/tex] = A'(9,0)

[tex]B(1, -2) \rightarrow (3 \cdot 1 , 3\cdot -2)[/tex] =B'(3,-6)

[tex]C(3, -5) \rightarrow (3 \cdot 3 , 3\cdot -5)[/tex] = C'(9,-15)

[tex]D(7, -1) \rightarrow (3 \cdot 7 , 3\cdot -1)[/tex] = D'(21, -3)




Ver imagen OrethaWilkison

Dilation involves changing the size of a shape

  • The dilation is an enlargement, and the scale of dilation is 3
  • The image of the vertices are (9,0), (3,-6), (9,-15) and (21,-3)

Question 3

The corresponding side lengths are represented as:

[tex]Blue = 6[/tex]

[tex]Black = 2[/tex]

So, the scale of dilation (k) is:

[tex]k = \frac {Blue}{Black}[/tex]

[tex]k = \frac {6}{2}[/tex]

[tex]k =3[/tex]

Hence, the dilation is an enlargement, and the scale of dilation is 3

Question (4)

The vertices are given as:

[tex]A = (3,0)[/tex]

[tex]B = (1,-2)[/tex]

[tex]C = (3,-5)[/tex]

[tex]D = (7,-1)[/tex]

And the scale factor is given as:

[tex]k =3[/tex]

So, the image of the dilation are:

[tex]A' = (3,0) \times 3 = (9,0)[/tex]

[tex]B' = (1,-2) \times 3 = (3,-6)[/tex]

[tex]C' = (3,-5) \times 3 = (9,-15)[/tex]

[tex]D' = (7,-1) \times 3 = (21,-3)[/tex]

Hence, the image of the vertices are (9,0), (3,-6), (9,-15) and (21,-3)

Read more about dilation at:

https://brainly.com/question/10686333

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