Answer:
The given inequality is
[tex]\frac{2y}{3} - 9 < y + 1[/tex]
Let y be a Real number such that 9 less than two third of that number is less than one added to that number.
We can find solution of the inequality also
1. keeping variable on one side and constant on another side, which gives
→y - [tex]\frac{2y}{3}[/tex] > -9 -1
→[tex]\frac{y}{3} > -10\\\\y> -30[/tex]
Answer:
Nine ⇒ less than two-thirds of number is less than the number ⇒ plus one.
Step-by-step explanation:
