Respuesta :

Answer:

[tex]f(x) = 4x + 3 \,,\,\,\,g(x) = 7x-6\\(f/g)(x)=\frac{4x+3}{7x-6}\,,\,\,\,7x-6\neq0\implies x\neq \frac{6}{7}\\\mbox{Domain:}\,\,\,x\in(-\infty,\frac{6}{7}) \cup (\frac{6}{7},+\infty)[/tex]

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