Respuesta :

remotecontrolbrain

Use the table of standardized normal cumulative function.

Look up the corresponding x' for the value z=0.9332: I found x'=0.8232 (approximately).

We know that x'=1.5x, so x = 0.8232/1.5 = 0.5488

Cricetus

The value of "x" will be "0.5488".

According to the question,

  • z = 0.9332

By using the standardized normal cumulative function,

  • [tex]x' = 0.8132[/tex]

We know,

→ [tex]x' = 1.5 x[/tex]

then,

→ [tex]x = \frac{x'}{1.5}[/tex]

By substituting the value, we get

      [tex]= \frac{0.8232}{1.5}[/tex]

      [tex]= 0.5488[/tex]

Hence, the above answer is appropriate.

Learn more about normal distribution here:

https://brainly.com/question/4426267

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