So, we need to make some equations to find this.
Let x be "one number"
x = (2y) +11
x+y = 2(x-y)
Now we can substitute
2y+11 +y = 2(2y+11)-2y
3y+11 = 4y+22-2y
3y+11 = 2y+22
y+11 = 22
y= 11
So the "Other number" is equal to 11.
Now, we can solve for x
x = 2y+11
x = 2(11) + 11
x = 22+11
x = 33
So, the numbers are 33 and 11
