Answer:
144
Step-by-step explanation:
The series is described by the problem statement as ...
... 0 +4 +8 +12 +... +32
= 4*(0 +1 +2 +... +8) . . . . . the first 9 multiples of 4, starting with 0
Now we know the sum of integers 1..n is given by n(n+1)/2. So for n=8, this is ...
... 8·9/2 = 36
Multiplying this by 4, we find the series sum to be ...
= 4·(sum of integers 0 .. 8) = 4·36 = 144
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Comment on the answer choices
It appears your answer choices may not include the value 144. That is unfortunate. You may want to ask your teacher to show you how to work this problem and reconcile the answer choices with the problem statement.
The 9-term series starting with 4 will have sum ...
... 4·(1 +2 +3 +... +9) = 4·(9·10)/2 = 4·45 = 180
