Answer:
It takes 2 seconds before the drop passes through another window ledge that is 16 ft above the ground.
Step-by-step explanation:
The formula to find time is
[tex]d=ut+\frac{1}{2}at^2[/tex]
Here the drop falls from a window which at a height of 80 ft.
Hence the initial velocity = 0 = u
Now when it passes through a widow at a height of 16 ft, it has covered a distance of = 80-16 = 64 ft = d
It is falling under the gravity so its acceleration = g = 9.8 m/s² = 32 ft /s²
Substituting the values in the formula we get
[tex]64=0(t)+\frac{1}{2}32t^2[/tex]
[tex]64=16t^2[/tex]
Dividing both sides by 16 we get
[tex]4=t^2[/tex]
Taking square root on both sides we get
[tex]t=2[/tex]
