List the known information:
[tex]x_0=207 \text{ m}\\v_0=-5.37 \text{ m/s}\\t=3.03 \text{ s}\\a=-g=-9.8 \text{ m/s}^2[/tex]
Use the kinematic equation [tex]v=v_0+at [/tex].
Plug in the given values:
[tex]v=-5.37 \text{ m/s}+(-9.8 \text{ m/s}^2)(3.03 \text{ s})=-35.064 \text{ m/s}[/tex]
This would be 35.064 m/s downward, or 35 m/s downward with significant figures taken into account.
