Respuesta :

Answer:

-3 and 3/2

Step-by-step explanation:

6x^3 - 2x^2 + x + 3

possible roots are  p/q  where p = factors of 3 and q are factors of 6

So from the 4 choices possible roots are -3 and 3/2

Rational root theorem is used to determine the possible roots of a function.

The potential roots are: -3 and 3/2

The function is given as:

[tex]\mathbf{f(x) = 6x^3 - 2x^2 + x+3}[/tex]

For a function,

[tex]\mathbf{f(x) = px^n +.........+q}[/tex]

The potential roots are:

[tex]\mathbf{Root = \pm\frac{Factors\ of\ q}{Factors\ of\ p}}[/tex]

So, we have:

[tex]\mathbf{q = \pm 1, \pm 3}[/tex] ---- factors of 3

[tex]\mathbf{p = \pm 1, \pm 2, \pm 3, \pm 6}[/tex] ---- factors of 6

The potential roots are:

[tex]\mathbf{Root = \frac{\pm 1, \pm 3}{\pm 1, \pm 2, \pm 3, \pm 6}}[/tex]

From the options, the potential roots are:

[tex]\mathbf{Root = -3, \frac{3}{2}}[/tex]

Read more about rational roots theorem at:

https://brainly.com/question/9353378

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