bryangon13
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What is the final temperature of a 27.2-gram wooden block that starts at 23.4°C and loses 759 joules of energy? The specific heat capacity of wood is 1.716 joules/gram degree Celsius. Use the formula Q = mCΔT.
A. 7.1°C
B. 10.9°C
C. 16.3°C
D. 39.7°C

Respuesta :

T = final temperature  of the block

T₀ = initial temperature of the block = 23.4 °C

Q = energy lost  from the wooden block = - 759 J

c = specific heat capacity of wood = 1.716 J/(g  °C)

m = mass of the wooden block = 27.2 g

Heat lost from the block is given as

Q = m c (T - T₀)

inserting the values

- 759 = (27.2) (1.716) (T - 23.4)

T = 7.1 °C

mahima6824soni

The final temperature of a 27.2-gram wooden block is 7.1 °C. The correct option is A.

What is temperature?

Temperature is the measurement of the hotness or coldness of the body. It is denoted by Kelvin.

By specific heat equation

[tex]Q = mc (T - T_\circ)[/tex]

where T = final temperature

T₀ is the initial temperature =23.4 °C

Q is lost energy from the block = - 759 J

c is specific heat = 1.716 joules/gram

m is the mass of the block = 27.2 g

Putting the values in the equation

[tex]\rm - 759 = (27.2) (1.716) (T - 23.4) = 7.1_\circ C[/tex]

Thus, the correct option is A is 7.1 °C.

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