Respuesta :
We know: 9 = 3²
Therefore [tex]\dfrac{1}{9}=\dfrac{1}{3^2}[/tex]
We know the property:
[tex]\dfrac{a^n}{a^m}=a^{n-m}[/tex]
Therefore [tex]\dfrac{1}{9}\cdot3^x=\dfrac{3^x}{3^2}=3^{x-2}[/tex]
We must find f(5). Put x = 5 to the equation of the function:
[tex]f(5)=3^{5-2}=3^3=3\cdot3\cdot3=27[/tex]
Answer: f(5) = 27.
The value of f(5) is 27 of function f(x) = 1/9(3)ˣ
What is the function?
The function is defined as mathematics expression defines a relationship between one variable and another variable. When we say that a variable quantity y is a function of a variable quantity x, we indicate that y depends on x and that value of x determines what value of y will be. This relationship can be expressed as follows: y = f (x)
What is Exponential Function?
An exponential function is defined as function has a constant as its base and a variable as its exponent.
In mathematical form an exponential function is a function of form f (x) = aˣ, where “x” is a variable and “a” is a constant which is called the base of the function.
For the function f defined by f(x) given as :
f(x) = 1/9(3)ˣ ,
To determine the value of f(5).
f(x) = 1/9(3)ˣ,
Substitute the value of x = 5 in the function,
f(5) = 1/9(3)⁵ , [ 3⁵ = 243 ]
f(5) = 1/9(243),
f(5) = 27
Hence, the value of f(5) is 27.
Learn more about function here :
brainly.com/question/12431044
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