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Please help! Polygon ABCDE rotates 45° clockwise about point F to form polygon FGHIJ, shown in the figure. Find the measure of each angle of polygon ABCDE.

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jacobricherson71

Polygon FGHIJ is the result of the rotation of ABCDE. 


A = F ⇒ 117°

B = G ⇒ 90°

C = H ⇒ 127°

D = I ⇒ 90°

E = J ⇒ 117°


The measure of angle BCD remains the same because the rotation involves the whole polygon. Thus, it is still 127°


Read more on Brainly.com - https://brainly.com/question/1591791#readmore

Sky50923

Answer:

m∠ABC = 117 °

m∠BCD = 90 °

m∠DEA = 90°

m∠CDE = 127°

Step-by-step explanation:

Since this is a series of rigind transformations, the angles of the figure do not change, so:

A=F= 117°

B=G=117°

C=H=90°

D=I=127

E=J=90°

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