Help with these questions please




Answer: 11
Step-by-step explanation:
6 to the log of base 6 cancels out leaving you with 11
*********************************************************************
Answer: [tex]\frac{16}{25}[/tex], [tex]\frac{4}{5}[/tex], 1, [tex]\frac{5}{4}[/tex], [tex]\frac{25}{16}[/tex], C
Step-by-step explanation:
f(x) = [tex](\frac{5}{4} )^{x}[/tex]
f(-2) = [tex](\frac{5}{4} )^{-2}[/tex] = [tex](\frac{4}{5} )^{2}[/tex] = [tex]\frac{16}{25}[/tex]
f(-1) = [tex](\frac{5}{4} )^{-1}[/tex] = [tex](\frac{4}{5} )^{1}[/tex] = [tex]\frac{4}{5}[/tex]
f(0) = [tex](\frac{5}{4} )^{0}[/tex] = 1
f(1) = [tex](\frac{5}{4} )^{1}[/tex] = [tex]\frac{5}{4}[/tex]
f(2) = [tex](\frac{5}{4} )^{2}[/tex] = [tex]\frac{25}{16}[/tex]
(-2, 16/25), (-1, 4/5), (0, 1) (1, 5/4), (2, 25/16)
Which graph shows the coordinates above? C
*********************************************************************
Answer: 6
Step-by-step explanation:
[tex](\sqrt[3]{3} )^{x}[/tex] = 9
[tex]3^{\frac{x}{3} }[/tex] = 3²
[tex]\frac{x}{3}[/tex] = 2
[tex](3)\frac{x}{3}[/tex] = 2(3)
x = 6
*********************************************************************
Answer: [tex]\frac{1}{3}[/tex]
Step-by-step explanation:
[tex]log_{2} \sqrt[3]{2}[/tex]
= [tex]log_{2} (2^{\frac{1}{3}} )[/tex]
log base 2 of 2 cancels out leaving you with [tex]\frac{1}{3}[/tex]