ANSWER
[tex]C_{41}=2[/tex]
EXPLANATION
This very simple to do.
First locate the entry in [tex]A_{41}[/tex] in matrix A. That is the entry in the intersection of the fourth row and first column of matrix A. This entry is [tex]7[/tex].
Then multiply by the scalar which is 2 to get,
[tex]2\times 7=14[/tex].
Next we locate the entry in [tex]B_{41}[/tex] in matrix B also. Which is [tex]4[/tex]. We multiply by the scalar of [tex]-3[/tex] to get,
[tex]-3\times 4=-12[/tex].
We now add these two corresponding entries to obtain,
[tex]14+-12=14-12=2[/tex]
See diagram
