A heating pad has several strips of heater wire connected in parallel.Consider eight of the wires, each with 4Ω resistances, connected to a 12V power source.given this scenario answer the following questions A.what is the total resistances of eight wires(they are in groups of two)? B.what is the total current?

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AL2006 AL2006 · Answer 1 · 2018-10-18T03:53:26+02:00

The question is going along fine, and then suddenly "groups of two" get thrown in. What that means is not clear at all.

Here's a solution assuming that 8 heater wires are all in parallel:

-- The resistance of each wire is 4 ohms.

-- If eight resistors, each 4 ohms, are in parallel, the total resistance is 0.5 ohm.

-- Current = (voltage)/(resistance)

Current = (12 volts) / (0.5 ohm)

Current = 24 Amperes.

Power dissipated by the heater = (voltage) x (current)

Power = (12 volts) x (24 Amps) = 288 watts, a nice toasty heating pad.

boffeemadrid boffeemadrid · Answer 2 · 2022-01-25T12:32:49+01:00

The total resistance and total current in the circuit is required.

The total resistance is [tex]2\ \Omega[/tex]

The total current is 6 A.

Voltage = 12 V

Number of resistances = 8

Resistance of each resistor = [tex]4\ \Omega[/tex]

2 groups of 4 wires are connected in parallel and they are connected to each other in series

Total resistance is

[tex]\dfrac{1}{R}=4\dfrac{1}{4}\\\Rightarrow R=1\ \Omega[/tex]

[tex]R=1+1=2\ \Omega[/tex]

Total current is

[tex]V=IR\\\Rightarrow I=\dfrac{V}{R}\\\Rightarrow I=\dfrac{12}{2}\\\Rightarrow I=6\ \text{A}[/tex]

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