Answer:
1.6 meters per second.
Step-by-step explanation:
We have been given an position function [tex]P(t)=0.8t^{2}[/tex] and we are asked to find the speed of the rock after 1 second.
Derivative of this function will give us speed function.
[tex]S(t)=2\cdot 0.8\cdot t[/tex]
[tex]S(t)=1.6\cdot t[/tex]
Now let us find derivative when t=1,
[tex]S(1)=1.6\cdot 1=1.6[/tex]
Therefore, the speed of the rock after 1 second will be 1.6 meters per second.
