so first you plug in for the seconds so for 1 second [tex]h = - 16t + 144 \\ h = ( - 16)(1) + 144 \\ h = - 16 + 144 \\ h = 138[/tex] now for 2 seconds [tex]h = - 16(2) + 144 \\ h = - 32 + 144 \\ h = 112[/tex] now for 3 seconds [tex]h = - 16(3) + 144 \\ h = - 48 + 144 \\ h = 96[/tex]
to find when the ball hits the ground plug in 0 for h [tex]0 = - 16t + 144 \\ - 144 = - 16t \\ \frac{ - 144}{ - 16} = \frac{ - 16t}{ - 16} \\ t = 9[/tex] answer is 9 seconds
