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Dana has only nickels in her hand and Ajah has exactly the same number of dimes and no other coins. Together they have a total of 90¢. How many coins is each person holding?

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puglife10
They would each be holding 6 coins

Building and solving an equation, it is found that each person is holding 6 coins.

  • We don't know the number of coins, so we call it x.
  • A nickel is worth $0.05, thus in total, Dana has 0.05x.
  • A dime is worth $0.1, thus in total, Ajah has 0.1x.
  • Together, they have 0.9, thus:

[tex]0.05x + 0.1x = 0.9[/tex]

[tex]0.15x = 0.9[/tex]

[tex]x = \frac{0.9}{0.15}[/tex]

[tex]x = 6[/tex]

Each person is holding 6 coins.

A similar problem is given at https://brainly.com/question/17096268

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