we know that
area of rectangle = length*width
Let's assume
length of rectangle is L
width of rectangle is W
[tex]A=L*W[/tex]
we are given
[tex]A=5x^3+19x^2+6x-18[/tex]
[tex]L=x+3[/tex]
now, we can find width
[tex]W=\frac{A}{L}[/tex]
now, we can plug values
[tex]W=\frac{5x^3+19x^2+6x-18}{x+3}[/tex]
we can use synthetic divison method
we get
[tex]W=\frac{5x^3+19x^2+6x-18}{x+3}=5x^2+4x-6[/tex]
[tex]W=5x^2+4x-6[/tex]
so, option-A...........Answer
