To solve this problem you must apply the proccedure shown below:
1. You have the following system of equations given in the problem above:
[tex]\left \{ {{3x+6y=3} \atop {2x-10y=44}} \right.[/tex]
2. By applying the Substitution method, you can solve the first equation for [tex]x[/tex]:
[tex]3x+6y=3\\x=\frac{3-6y}{3}[/tex]
3. Simplifying:
[tex]x=1-2y[/tex]
4. Now, substitute [tex]x=1-2y[/tex] into the second equation:
[tex]2x-10y=44\\2(1-2y)-10y=44[/tex]
5. You must apply the distributive property and solve for [tex]y[/tex]:
[tex]2-4y-10y=44\\-14y=42\\y=\frac{42}{-14}\\y=-3[/tex]
6. Now, substitute the value of [tex]y[/tex] into the first equation and solve for [tex]x[/tex]:
[tex]3x+6(-3)=3\\3x-18=3\\x=\frac{21}{3}\\x=7[/tex]
Therefore, the answer is: [tex](x,y)=(7,-3)[/tex]
