we are given
[tex]\frac{2x^4-x^3-15x^2+3x}{x+3}[/tex]
we can also write as
[tex]\frac{2x^4-x^3-15x^2+3x+0}{x+3}[/tex]
now, we can use synthetic division method
so, we get
[tex]\frac{2x^4-x^3-15x^2+3x+0}{x+3}=(2x^3-7x^2+6x-15)+\frac{45}{x+3}[/tex]..................Answer
