Respuesta :
3*3=9
3 *-8i = -24i
8i *3 =24i
8i*-8i = -64i^2 or i^2 =-1. -64*-1=64
-24i + 24i =0
9+64= 73
Answer 73
3 *-8i = -24i
8i *3 =24i
8i*-8i = -64i^2 or i^2 =-1. -64*-1=64
-24i + 24i =0
9+64= 73
Answer 73
The product of each pair of complex conjugates is 73.
Given to us,
(3+8i)(3-8i)
We must know:
a.) [tex]i = \sqrt{(-1)}[/tex]
b.) [tex]i^2 = (\sqrt{(-1})^2 = -1[/tex]
c.) [tex](a+b)(a-b)=a^2-b^2[/tex]
The product of these complex conjugates can be found out in the following ways:
a.) Solving by taking the product
[tex](3+8i)(3-8i)\\= 9-24i+24i -64i^2\\=9-64(i^2)\\=9-64(-1)\\=9+64\\=73[/tex]
b.) Solving using the identity,
[tex](3+8i)(3-8i)\\=(3)^2-(8i)^2\\= 9 -(-64)\\= 9+64\\=73[/tex]
Hence, the product of each pair of complex conjugates is 73.
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