Please help if you can.
Suppose a family replaces ten 60-watt incandescent bulbs with ten 30-watt fluorescent lamps. If each light was used for 4 hours per day and the cost of electricity was 10.0 ¢/kWh, how much money would they save in a year? Explain your answer.

If we started off with 60 Watt bulbs and now are replaced by 30 Watt bulbs, the total power of all bulbs = 30 times 10 = 300 W now each bulb used for 4 hours daily so total energy consumed daily. They would save $43.80.

So in the gizmos, the answer would be $43.80 saved in a year.

Hope this helps

AKA:I did this already that is how I know.

:)

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pstnonsonjoku pstnonsonjoku · Answer 2 · 2021-11-02T15:21:44+01:00

by using ten 30-watt fluorescent lamps, you save 4380 ¢ in a year.

The unit that is commonly used to measure the power consumed is KWhr. That means we have to obtain the energy consumed in KWhr in both cases as follows;

ten 60-watt incandescent bulbs = 10 × 60/1000 × 4 hr =2.4 KWhr

ten 30-watt fluorescent lamps = 10 × 30/1000 × 4 hr = 1.2 KWhr

The cost of operating ten 60-watt incandescent bulbs for four hours = 2.4 KWhr × 10.0 ¢/kWh = 24¢

The cost of operating ten 30-watt fluorescent lamps = 1.2 KWhr × 10.0 ¢/kWh = 12 ¢

Hence, by using ten 30-watt fluorescent lamps, you save in a year, 365(24¢) - 365(12 ¢) = 4380 ¢

Learn more: https://brainly.com/question/22824409

Please help if you can. Suppose a family replaces ten 60-watt incandescent bulbs with ten 30-watt fluorescent lamps. If each light was used for 4 hours per day and the cost of electricity was 10.0 ¢/kWh, how much money would they save in a year? Explain your answer.

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Please help if you can.
Suppose a family replaces ten 60-watt incandescent bulbs with ten 30-watt fluorescent lamps. If each light was used for 4 hours per day and the cost of electricity was 10.0 ¢/kWh, how much money would they save in a year? Explain your answer.