[tex] \frac{t - 12}{2} = \frac{3t}{2} - 3 \\ \frac{t - 12}{2} = \frac{3t}{2} - \frac{3 \times 2}{1 \times 2} \\ \frac{t - 12}{2} = \frac{3t}{2} - \frac{6}{2} \\ \frac{t - 12}{2} = \frac{3t - 6}{2} \\ t - 12 = 3t - 6 \\ 3t - t = - 12 + 6 \\ 2t = - 6 \\ t = \frac{ - 6}{2} \\ t = - 3[/tex]
The answer is t = -3
