What is the solution to this?

[tex]\frac{6x+8}{2}[/tex] - 4 = 3x
[tex]\frac{6x+8}{2}[/tex] = 3x + 4 added 4 to both sides
6x + 8 = 2(3x + 4) multiplied both sides by 2
6x + 8 = 6x + 8 distributed 2 on the right side
8 = 8 subtracted 6x from both sides
TRUE
Since this makes a trues statement, then there are infinite solutions
Answer: All real numbers
6x + 8/2 - 4 = 3x
multiply numerator by denominator to get rid of fraction:
12x + 16 - 4
now you move the 12x over to the other side of the equation so that we have all the x's together.
16 - 4 = 3x-12x
now you solve it:
12 = -9x
12/-9 = x
x= negative 4/3
Answer by Ayden Ratnasekera