Respuesta :
Answer:
The minimum frequency required to ionize the photon is 111.31 × [tex]10^{37}[/tex] Hertz
Given:
Energy = 378 [tex]\frac{kJ}{mol}[/tex]
To find:
Minimum frequency of light required to ionize magnesium = ?
Formula used:
The energy of photon of light is given by,
E = h v
Where E = Energy of magnesium
h = planks constant
v = minimum frequency of photon
Solution:
The energy of photon of light is given by,
E = h v
Where E = Energy of magnesium
h = planks constant
v = minimum frequency of photon
738 × [tex]10^{3}[/tex] = 6.63 × [tex]10^{-34}[/tex] × v
v = 111.31 × [tex]10^{37}[/tex] Hertz
The minimum frequency required to ionize the photon is 111.31 × [tex]10^{37}[/tex] Hertz
Explanation:
Relation between energy and frequency is as follows.
E = [tex]h \nu[/tex]
where, E = energy
h = planck's constant = [tex]6.626 \times 10^{-34}[/tex] Js
[tex]\nu[/tex] = frequency
As it is given that value of energy is 738 kJ/mol.
E = [tex]\frac{738 \times 1000 J}{6.022 \times 10^{23}}[/tex]
= [tex]1.22 \times 10^{-18}[/tex] J
Hence, putting the given values into the above formula as follows.
E = [tex]h \nu[/tex]
[tex]1.22 \times 10^{-18}[/tex] J = [tex]6.626 \times 10^{-34} Js \times \nu[/tex]
[tex]\nu[/tex] = [tex]1.84 \times 10^{15}[/tex] per second
Thus, we can conclude that [tex]1.84 \times 10^{15}[/tex] per second is the minimum frequency of light which is required to ionize magnesium.
