contestada

what is the specific latent heat of fusion for a substance that takes 550 kj to melt 14 kg at 262 K

Respuesta :

znk

q = mL

L = q/m = 550 kJ/14 kg = 39 kJ/kg

Answer:

Specific latent heat = 39.3 kJ/Kg

Explanation:

Given:

Mass of the substance = 14 kg

Energy = 550 kJ

Temperature = 262 K

To determine:

The specific latent heat of the substance

Calculation:

The amount of heat (Q) required to change the phase or the physical state of a kilogram (kg) a substance at constant temperature is termed as specific latent heat.

[tex]LatentHeat = \frac{q}{m}=KJ/Kg[/tex]

For the given substance:

[tex]LatentHeat = \frac{550kJ}{14Kg}=39.3kJ/Kg[/tex]

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