[tex] 16x^2 + 8x + 1 = 0\\\\a=16\qquad b=8\qquad c=1\\\\\\\Delta=b^2-4ac=8^2-4\cdot16\cdot1=64-64=\boxed{0} [/tex]
Δ = 0 so we have a double root (answer A).
Answer:
Step-by-step explanation:
If a quadratic equation is defined as[tex]ax^2+bx+c=0[/tex], then the discriminant of the equation is
[tex]D=b^2-4ac[/tex]
If D>0, then the equation has two real roots, it may be rational or irrational.
If D=0, then the equation has one real root.
If D<0, then the equation has no real roots and 2 complex roots.
The given equation is
[tex]16x^2+8x+1=0[/tex]
Here, a=16, b=8 and c=1.
The value of the discriminant is
[tex]D=(8)^2^2-4(16)(1)[/tex]
[tex]D=64-64[/tex]
[tex]D=0[/tex]
The value of the discriminant is 0, it mean the given equation has two same real root or double root.
Therefore the correct option is 1.
