[tex] \sqrt{5x} [/tex] + √6 = √9
The first step is to get [tex] \sqrt{5x} [/tex] by itself. We can do this by subtracting [tex] \sqrt{6} [/tex] from each side, and simplifying [tex] \sqrt{9} [/tex]
[tex] \sqrt{5x} [/tex] = 3 - [tex] \sqrt{6} [/tex]
Now we square both sides
5x = (3 - [tex] \sqrt{6} [/tex])²
Using the formula (a - b)² = a² -2ab + b², (3 - [tex] \sqrt{6} [/tex])² = 15 - 6[tex] \sqrt{6} [/tex]
5x = 15 - 6[tex] \sqrt{6} [/tex]
x = [tex] \frac{15 - 6\sqrt{6}}{5} [/tex]
