Help me on this question please!
An inequality is shown below:

−np − 6 ≤ 3(c − 5)

Which of the following solves for n?

n ≥ − the quantity 3 times c minus 21 all over p
n ≥ − the quantity 3 times c minus 9 all over p
n ≤ − the quantity 3 times c minus 21 all over p
n ≤ − the quantity 3 times c minus 9 all over p

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perim perim · Answer 1 · 2018-07-21T01:10:31+02:00

it is the 2 sentence

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FelisFelis FelisFelis · Answer 2 · 2019-08-13T14:21:00+02:00

Answer:

The correct option is B) [tex]n\geq \frac{-3c+9}{p}[/tex].

Step-by-step explanation:

Consider the provided inequality:

[tex]-np - 6 \leq 3(c - 5)[/tex]

Now distribute 3 inside the parentheses.

[tex]-np - 6\leq 3c - 15[/tex]

Add 6 on both the side of the inequality:

[tex]-np-6+6\leq 3c-15+6[/tex]

[tex]-np\leq 3c-9[/tex]

Now, multiply both the sides by a negative sign and reverse the sign of inequality.

[tex]np\geq -3c+9[/tex]

Divide both the sides of the inequality by p.

[tex]n\geq \frac{-3c+9}{p}[/tex]

Now consider the provided options.

By observing the provided option it can be concluded that the correct option is B) [tex]n\geq \frac{-3c+9}{p}[/tex].