Answer:-
240.558 K
Explanation:-
Number of Moles n = 1
Pressure P = 20 kilopascals = 20 KPa
Volume V = 100 L
We know Universal Gas constant R = 8.314 L kPa K−1 mol−1
Using the relation
PV = nRT
Temperature T = P x V / ( n x R)
T = 20 KPa x 100 L / ( 1 mol x 8.314 L kPa K−1 mol−1 )
= 240.558 K
