Normal form problem [see attachment]

I'm not familiar with the notation but I'll guess this refers to the equation:
[tex] p = x \cos \phi + y \sin \phi [/tex]
[tex] 11\pi/6 [/tex] is -30 degrees
[tex] 4 \sqrt{3} = x (\sqrt{3}/2) - y/2 [/tex]
[tex] \sqrt{3} x - y - 8 \sqrt{3} = 0 [/tex]
Choice b